Thursday, 23 October 2014

general relativity - What is the relationship between $a$ and $m$


$a$ is defined in HERE


What is the relationship between the length-scale $a$ and the mass $m$?



Answer



According to Schutz (chapter 11) for the Schwarzschild metric $dr/d\phi$ is given by:



$$ \left(\frac{dr}{d\phi}\right)^2 = \frac{E^2}{L^2}r^4 - \left(1 - \frac{r_s}{r}\right)\left(\frac{r^4}{L^2} + r^2\right) $$


where:


$$\begin{align} E &= \frac{p_0}{m} \\ L &= \frac{p_\phi}{m} \end{align}$$


Comparing this with the equation in the Wikipedia article we find:


$$ a = L = \frac{p_\phi}{m} = r^2\frac{p^\phi}{m} $$


Though this makes $a$ an angular velocity rather than a length scale.


No comments:

Post a Comment