electrostatics - What happens to half of the energy in a circuit with a capacitor?

For a simple circuit with a battery supplying a voltage $V$ to a capacitor, let us assume that the charge on the capacitor is $Q$. Now, the work done by the battery or the energy supplied is given by the relation:

$$W=QV$$

But the energy stored in the capacitor is given by:

$$U = \tfrac12 QV$$

The value of $Q$ as well as that of $V$ should be the same in both the equations.

Now my question is, where is the other half of the energy that the battery supplied?