I'm looking for a solution to make number $75$ with numbers $1$ $9$ $6$ $2$ in that order and the same rules as in Use 2 0 1 and 8 to make 67.
Here a copy of those rules:
You must use all 4 digits. Only the digits $1$, $9$, $6$, and $2$ can be used in that order.
You can make multi-digit numbers out of the numbers. Examples: $19$, $96.2$The square function may NOT be used. Nor may the cube, raise to a fourth power, or any other function that raises a number to a specific power. You may use the ^ operation if you use a digit, for example, $(1 + 9)^6 - 2!$ is acceptable (if you're trying to get $999998$), because 1, 9, 6, and 2 are used. However, $19 ^ 2 / 6 + 2$ can't be used to get $62.166...$ because it uses an extra 2.
Sorry, but the integer function may NOT be used. Nor may the round, floor, ceiling, or truncate functions.
$+$, $-$, $\times$, $\div$ or $\frac{\Box}{\Box}$, $()$, $!$, $\sqrt{\Box}$, ${\Box}^{\Box}$, and $!!$ may be used for functions.
Please no brute-force methods. Good luck.
Answer
how about this?
$$1\times 9/.6/.2$$
this is allowed right?
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