newtonian mechanics - How much weight do you feel during negative g-forces?

My physics teacher told me and some other students that when you experience negative g-forces, your weight equals:

$$\frac{mass}{g_{force}}$$ So when the g-forces equal -4 g your mass will be: $$\frac{mass}{-4}$$ Now I don't think this is true, because this doesn't work when the g-forces are positive. And also to follow the pattern (example pattern):)

$45 \, \mathrm{kg} \times 3g = 1350\, \mathrm N$

$45 \, \mathrm{kg} \times 2g = 900\, \mathrm N$

$45 \, \mathrm{kg} \times 1g = 450 \, \mathrm N$

$45 \, \mathrm{kg} \times 0g = 0\, \mathrm N$

$45 \, \mathrm{kg} \times (-1g) = -450\, \mathrm N$

$45 \, \mathrm{kg}\ /\;(-1g) = -450 \, \mathrm N$

$45 \, \mathrm{kg} \times (-2g) = -900\, \mathrm N$

$45 \, \mathrm{kg}\ / \;(-2g) = -225\, \mathrm N$

Which one is true?