The condition for a field →E to be conservative is: ∇×→E=→0. In electrostatics, ∇×→E=→0 is followed strictly, but Faraday's law says that: ∇×→E=−∂∂t→B
Does this mean when ∂∂t→B≠→0, the electric field is not conservative?
The condition for a field →E to be conservative is: ∇×→E=→0. In electrostatics, ∇×→E=→0 is followed strictly, but Faraday's law says that: ∇×→E=−∂∂t→B
What is stagnation point in fluid mechanics. At the open end of the pitot tube the velocity of the fluid becomes zero.But that should result...
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