Wednesday, 9 May 2018

acoustics - In terms of the Doppler effect, what happens when the source is moving faster than the wave?


I'm just trying to understand this problem from a qualitative perspective. The Doppler effect is commonly explained in terms of how a siren sounds higher in pitch as it is approaching a particular observer. I understand this is because the velocity of the wave is constant and so the frequency of the waves increase as they are bunched together. What would happen if a siren was mounted on say a plane traveling at a supersonic speed? To clarify what would the observer observe/hear? Apologies if my question is not phrase very well my knowledge of physics is very rudimentary.



Answer




The first image shows an object traveling at Mach 1 ($v=c$). The second one shows the object traveling at some supersonic velocity ($v>c$). For both the cases, the longitudinal pressure waves pile up. Say the observer is standing in the ground and the object is traveling at $c$. The observer can't hear the pitch of sound because, the waves reach him all at once and hence, he'd hear a loud "bash". The most necessary thing is that he had to wait until the source arrives. When the source is directly overhead, he hears the shock waves.


When the object breaks the sound barrier (supersonic), it's somewhat worse. The same loud "thump" is produced here. But, the observer would notice a delay in sound (i.e) he has to wait for the shock waves to reach him. There's also this Mach cone produced by these waves since the waves group so fast behind the object. And so, there's a region of high pressure at first followed by a low pressure zone. Thus, if the object passes by in some comparable distance, it makes a lot of disturbance, "breaking things", etc...



The comic thing is, for someone inside the aircraft, he can still speak with his partner, can hear the bump of a ball on the plane, etc. The problem is only for the distant observer who suffers...


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