We know that work done ON the spring is given by the integral ∫kxdx=12kx2 if we start from x=0 .But what if I apply more force on the spring.Wouldn't I be doing more work on it? Why isn't this integral encapsulating this idea? Why should I assume that I just applied a little more force than the spring to move it? Any help will be seriously appreciated.
Sunday, 19 August 2018
forces - Why isn't the work done on the spring encapsulating this idea?
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