Tuesday 14 August 2018

quantum mechanics - Can isotropic states have bound entanglement?


Let us consider the maximally entangled state \begin{equation} |\psi\rangle=\frac{1}{\sqrt{n}}(|0,0\rangle+\cdots+|n-1,n-1\rangle) \end{equation} and construct the pseudo-pure state \begin{equation} \rho_\lambda=(1-\lambda)|\psi\rangle\langle\psi|+\lambda\frac{I_{n^2}}{n^2}, \end{equation} where $I_{n^2}$ is the identity matrix and $0\leq\lambda\leq1$. I was told that for any dimension $n$ and for any $\lambda$, $\rho_\lambda$ is either separable or entangled which can be determined by partial transpose. It can be rephrased as



There does not exists any dimension $n$ and any $\lambda$ such that the corresponding $\rho_\lambda$ is a bound entangled state.



I could not find out the proof and could not make one by myself. Can someone give me a proof or at least refer a paper containing the proof. Advanced thanks for any suggestion.


ADDITION: Also the same question can be asked for the case, when the coefficients of $|j,j\rangle$ are non-uniformly distributed nonzero complex numbers (such that the sum is $1$).




No comments:

Post a Comment

Understanding Stagnation point in pitot fluid

What is stagnation point in fluid mechanics. At the open end of the pitot tube the velocity of the fluid becomes zero.But that should result...