...By quantizing we the get the following Hamiltonian operator
ˆH=∑kℏω(k)(ˆn(k)+12)
where ˆn(k)=ˆa†(k)ˆa(k) is the number operator of oscillator mode k with eigenvalues nk=0,1,2,….Using the quantum canonical ensemble show that the internal energy E(T) is given by>
E(T)=⟨H⟩=E0+∑kℏω(k)eβℏω(k)−1
where E0 is the sum of ground state energies of all the oscillators.
I started this by calculating the partition function
Z=∑Γe−βH(Γ)=∑Γe−β(∑kℏω(ˆn(k)+12))
but I cannot see the thought process behind evaluating these, particularly with respect to the summations. This is a common problem I have found.
I would then go on to use E=−∂lnZ∂β
Answer
Quantum mechanically the general expression you want for the partition function is Z=Tr(e−βH),
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