Friday, 31 October 2014

homework and exercises - Calculating quantum partition functions




...By quantizing we the get the following Hamiltonian operator


ˆH=kω(k)(ˆn(k)+12)

where ˆn(k)=ˆa(k)ˆa(k) is the number operator of oscillator mode k with eigenvalues nk=0,1,2,.


Using the quantum canonical ensemble show that the internal energy E(T) is given by>


E(T)=H=E0+kω(k)eβω(k)1


where E0 is the sum of ground state energies of all the oscillators.



I started this by calculating the partition function


Z=ΓeβH(Γ)=Γeβ(kω(ˆn(k)+12))

(Γ is a microstate of the system)


but I cannot see the thought process behind evaluating these, particularly with respect to the summations. This is a common problem I have found.


I would then go on to use E=lnZβ




Answer



Quantum mechanically the general expression you want for the partition function is Z=Tr(eβH),

where Tr means the trace (i.e. sum over micro-states). Now you can use the fact that the modes are independent, so that quantum Boltzmann operator eβH factorises into a product. This means that you can evaluate the trace over each oscillator mode separately: Z=Tr(eβH)=Tr(keβHk)=kTrk(eβHk)=kZk
where Trk means the trace over only the Hilbert space of mode k, and Hk=ω(k)(ˆn(k)+12).
Now Trk means simply averaging over all the possible states in the Hilbert space, which you might as well choose to be the eigenstates of the number operator ˆn(k)|mk=mk|mk, with mk=0,1,2,. So you have to evaluate Zk=Trk(eβHk)=mk=0mk|eβHk|mk.


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