Saturday 7 October 2017

quantum field theory - Yang Mills Hamiltonian: why do we use the Weyl's temporal gauge?


Do you know why in the quantization of $SU(2)$ Yang-Mills Gauge Theory, it is always chosen the Weyl (temporal) gauge to derive the Hamiltonian?


Is it possible to fix another gauge?



Answer



Formally, the gauge-invariant observables do not depend on the choice of gauge-fixing condition (such as, e.g., Lorenz gauge, Coulomb gauge, axial gauge, temporal gauge, etc). Similarly, the Hamiltonian can formally be gauge-fixed in any gauge.


However, it is my understanding that to avoid the Gribov problem, an algebraic (rather than a differential) gauge-fixing condition is preferred. See also the footnote on p. 15 in S. Weinberg, Quantum Theory of Fields, Vol 2.



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