Thursday 30 November 2017

Error propagation rounding



hope I am right in this section.



I am unsure with error propagation. When calculation the error in a titration, many errors has to be taken into account:


Error in Glassware/ Error in Balance/ Error in Burette etc.


I learned that the absolute and relative error have only 1 significant figure and that the total amount is rounded to the decimal place of the error.


Therefore 5.34532g ± 0.001428g would be 5.345g ± 0.001g


The relative error is 0.001g/5.345g = 0.00018709 = 0.0002 If there is an experiment with a lot of steps and error propagation wouldn't the rounding of all the errors in every single step change the result a lot? Wouldn't rounding the error just in the end make more sense?


Many thanks in advance.




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