So I am working on this experiment on X-ray and kinda stuck on this last and following section.
I have done the measurements and plotted the graph as required in 1. and 2. See below,
However, I am afraid my graph doesn't look much similar to the graph from Kaye and Laby[3,p. 4.2.2 graph], the one below.
I would be very grateful if someone can please help me with and explanation to point 3. of the task and also the following 2 questions, Question 2 and Question 3. Thanks in advance.
Link to Kaye and Laby [3,p. 4.2.1 table]: http://www.kayelaby.npl.co.uk/atomic_and_nuclear_physics/4_2/4_2_1.html
Answer
The Kα X-ray emission is due to an L-shell electron falling into the K-shell with the emission of a photon.
The Kβ X-ray emission is due to an M-shell electron falling into the K-shell with the emission of a photon with a higher energy than that of a Kα photon.
As the atomic number increases so does the energy of the K-photons.
In the reverse process an incoming photon, if it has enough energy, can knock out an electron which is in the K-shell.
You will note that the energy of an incoming photon has to be greater than Kα, Kβ etc photons because the incoming photon has to remove the electron in the K-shell from the atom completely not just promote the electron into a higher energy level.
So for a given element, the energy of the K-edge is greater than the K-photons.
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