Is it possible to determine the position of a particle undergoing circular motion, in x-y coordinates, at any given time and velocity?
I'm thinking it has something to do with π
Answer
Yes, unless you want to be very picky. The coordinates are described by the trig functions sine and cosine.
Suppose something is moving on a circle with radius R, so its x and y coordinates obey
x2+y2=R2
If it moves at a uniform velocity of v, then the angle its path subtends is linear in time (by dimensional analysis), so we can define the angle θ as
θ=vt/R
One full rotation turns out to be an angle of about 6.28, but it's really a transcendental number, 2π.
If you draw a circle, then draw the angle from the equation above, you find a unique intersection point that tells you where the object is. If you project that point onto the x and y axes, you've graphically determined the coordinates.
The coordinate you obtain, for a given angle, is linear in R (again by dimensional analysis, coupled with a feature of Euclidean geometry - that it has no innate length scale), so if we divide the coordinates by R we get two functions that map [0,2π)→[−1,1] because −1 and 1 are the minimum and maximum values, since −R and R are the minimum and maximum values of the coordinates.
These functions are give the names "cosine" and "sine", and we say
x/R=cosθ
y/R=sinθ
The sine and cosine functions can be represented as infinite series,
cosθ=1−θ2/2+θ4/24−…
sinθ=θ−θ3/6+θ5/120−…
We know many of the properties of these functions, and they are used extensively in mathematics and physics. You can calculate their values to high precision with a computer. However, we cannot simply write down exactly what sin(1) is in any simple way that you can explain to an elementary-school student. If you want to know what it is, you can simply use a calculator, like this.
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