Monday, 27 April 2015

forces - Work done against gravity



The work done against gravity is $mgh$, well at least that's what my textbook says. I have a question: I can apply a force say 50N, so total work done = $mgh + mah$. Where $ma$ = Force. But the truth is irrespective of the force applied, the work done against gravity is always $mgh$. Why?


For example, when I move an object with a force, the work done is more, so work depends on the Force. But in case of gravity it always depends upon the weight



Answer



If I take a mass $m$ and apply a force $F$ (greater than $mg$) to it for a distance $h$ upwards then I will do work of:


$$ W = Fh \tag{1} $$


The force $F$ has to be greater than the force due to gravity, $mg$, or the object won't move upwards, so let's write the force I apply to the mass as:



$$F = mg + F'$$


then equation (1) becomes:


$$\begin{align} W &= (mg + F')h \\ &= mgh + F'h \end{align}$$


and the first term $mgh$ is work done against gravity while the second term is the work done to increase the velocity of the mass i.e. after the distance $h$ the velocity of the object will be given by:


$$ \tfrac{1}{2}mv^2 = F'h $$


or:


$$ v = \sqrt{\frac{2F'h}{m}} $$


So if you apply any force $F$ over a distance $h$ then subtract off the increase in the kinetic energy you'll be left with an amount of energy equal to $mgh$. That's why the work done against gravity is always $mgh$.


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