I am working on a problem in which there is a rectangular, perfectly conducting waveguide with side lengths 2D along the x-axis and 3D along the y-axis. We are supposed to find the values of m and n for which the TEmn modes can be excited if the cutoff frequency is 72ω10, where ωmn is the cutoff frequency for the mode.
My main problem with this is I'm unsure what it means for the TEmn modes to be excited, nor what the excitation frequency is. The magnetic field corresponding to the TEmn mode is:
Bz=B0cos(mπx3D)cos(nπy2D)
The cutoff frequency is:
ωmn=cπ√(m/3D)2+(n/2D)2
4m2+9n2<49
I then concluded that the modes were:
TE10,TE01,TE11,TE20,TE02,TE12,TE21,TE30,TE31
Answer
My main problem with this is I'm unsure what it means for the TEmn modes to be excited
This means, you applied a signal to the input end of the waveguide that has non-zero overlap with the mode in question.
For example, this can be done with a little antenna projected into the waveguide and fed by a coax or other transmission line.
(image source: radartutorial.eu)
To answer your title's question, The excitation frequency is whatever frequency you applied to the antenna to feed energy into the waveguide.
We are supposed to find the values of m and n for which the TEmn modes can be excited
In my opinion, this is a poor way to word the question. You can excite any mode you like, however that mode may produce evanescent rather than travelling waves at the excitation frequency, and thus not be useful for transmitting power or signals along the waveguide. A better wording would be "Find the values of m and n for all the TEmn modes that are propagating modes [at some frequency]".
No comments:
Post a Comment