I have been studying quantum mechanics, specifically angular momentum, but I have a question that concerns raising and lowering operators as a whole. For total angular momentum, you can define: J±=Jx±iJy
An analysis of this problem shows that: [Jz,J±]=±ℏJ±
However, while this approach is very clean cut, in my mind it doesn't exactly show that the eigenvalues of Jz exist only in increments of ℏ. For instance, if I were able to find some arbitrary set of operators W±, such that [Jz,W±]=±(ℏ/4)W±, then I could easily show by the logic above that the eigenvalues of Jz exist in increments of ℏ/4. So then, what guarantees that I cannot find such operators? More specifically, what part of the "raising and lowering operator" method guarantees that there are not more possible eigenvalues of Jz (or any operator), than those found using raising and lowering operators?
Answer
The formal answer lies in representation theory, in this case, the representation theory of the Lie algebra su(2), which is spanned by the three operators Jz,J+,J−. That there are no more eigenvalues of Jz than those found by the ladder operator method follows from two facts:
Every representation of su(2) is completely decomposable, i.e. the direct sum of irreducible representations.
The irreducible representations of su(2) are precisely the "spin representations" of physics, labeled by the half-integer largest eigenvalue ("highest weight") s of Jz, which have dimension 2s+1, consisting of the states with eigenvalues −s,−s+1,…,s−1,s.
s has to be half-integer because one can directly show that if s is the highest weight, then the lowest eigenvalue is −s, and if the difference between the highest and the lowest weight were not an integer, we would be able to reach an even lower weight by appling the lowering operator to the highest weight state.
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