It is known that there is solution of Einstein's equations for charged black hole. Reissner–Nordström metric in case of non-rotating charged black hole and for rotating charged black hole is a Kerr–Newman metric.
In Reissner–Nordström metric I can calculate electric field, it has following form $$ F_{0r}=-F_{r0}=\frac{Q}{r^2} $$ But I can not understand the following thing. In my point of view when two charged particle are interact, they exchange photons between each other. If I apply this argumentation in case on interacting between charged black hole and probe charge, I will get zero force due to black hole can not emit photon and absorb all photon. Can our explain how it works in quantum point of view(I mean QED and not Quantum gravity!!).
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