Consider the following extract from page 2 of this paper.
AdS3 is the SL(2,R) group manifold and accordingly has an SL(2,R)L×SL(2,R)R isometry group. In order to define the quantum theory on AdS3, we must specify boundary conditions at infinity. These should be relaxed enough to allow finite mass excitations and the action of SL(2,R)L×SL(2,R)R, but tight enough to allow a well-defined action of the diffeomorphism group.
SL(2,R)L×SL(2,R)R encodes global transformations of AdS3:
- These transformations transform a physical state into a different physical state.
- These transformations reach infinity.
Local spacetime diffeomorphisms of AdS3 encode gauge transformations of AdS3:
- These transformations transform a physical state into itself.
- These transformations do not reach infinity.
Why must boundary conditions on a spacetime be relaxed enough to allow the action of global transformations, but tight enough to allow a well-defined action of the local diffeomorphism group.
I know that global transformations and the diffeomorphism group are definitely in tension, but I do not understand what the words relaxed enough, tight enough and well-defined mean.
Answer
By "boundary conditions" (BCs) in the AdS/CFT (or equivalently in the Graham-Fefferman) settings, we don't mean boundary conditions ON the boundary r=∞, but rather fall-off conditions NEAR the boundary r→∞. One the GR side, one should specify fall-off conditions on the metric gμν. The actual BCs are usually a result of somewhat messy calculations.
The BCs should for starters:
be relaxed enough to allow the group action of global asymptotic symmetry transformations & finite mass excitations, e.g. multiple stars & black holes, because we want the model to be able to accommodate and describe these.
be tight enough (i.e. fall-off fast enough for r→∞) for the Einstein-Hilbert action integral SEH[g] of the allowed metrics gμν to be well-defined with a finite value, possibly after renormalization.
be consistent with the EFE.
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