A simple pendulum suspended from the ceiling of a stationary lift has period T0. When the lift descends at steady speed, the period is T1. When the lift descends with constant downward acceleration, the period is T2. Explain why T0=T1<T2.
I know that for small angles of oscillations, T≈2π√lg where l is the length of the pendulum. For the first two cases, since ∑F=0, the value of g is apparently the same. However, I am unable to explain why the period is largest for T2. If g is the same for all cases, shouldn't their periods be the same?
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