Thursday, 10 December 2015

newtonian mechanics - Work done by gravity on falling object does not seem to equal change in mechanical energy


So I have some confusion here, I am sure I knew this at some point. Let's say an object of 10 kg is dropped from a height of 10 m. When it reaches the ground, the work done on the object should be the force ($mg$) x distance or 10 kg x 9.8 m/s/s x 10 m. That gives 980 joules of work done on the object by gravity.


But the object did not gain 980 joules of mechanical energy. It lost 980 joules of GPE and gained 980 joules of kinetic energy (up to the point of it reaching ground level).


Using the change in GPE and KE, it looks like no work was done on the object because the loss in GPE equals the gain in KE.


So


a) am I right that no net work was done on the car by sum of all forces?


b) is the work done by gravity equal to force time distance, or is it equal to the change in mechanical energy of the object which is zero?





No comments:

Post a Comment

Understanding Stagnation point in pitot fluid

What is stagnation point in fluid mechanics. At the open end of the pitot tube the velocity of the fluid becomes zero.But that should result...