That's a hollow conducting sphere link
My charge is at P (10uC). R = 0.15m. PS = 0.05m. DS = 0.35m. What's the electric field at point D?
Answer
Assuming that the point charge is the only charge in the sphere, the electric field will simply follow from Gauss's law:
→E=14πϵqpr2PDˆrPD
Where ˆrPD is a unit vector pointing from P to D. Note that in this equation, ϵ is not the permittivity of free space, but rather the permittivity of the material in the sphere. So there will be a dielectric constant k associated with the sphere, and the permittivity can be calculated as kϵ0, where ϵ0 is 8.85×10−12Fm, as usual.
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