In the usual (x,y,z) system of coordinates, if we expand the Maxwell's curls equations for phasors
∇×E=−Jm−jωμH ∇×H=J+jωϵE
we obtain equations like the following:
∂Hy∂z−∂Hz∂y=Jx+jωϵEx
Now, let E′, H′, J′, J′m be a new field (with its new sources). In particular we have
H′y=Hy H′z=−Hz J′x=−Jx E′x=−Ex
The equation (1) for this field becomes
∂H′y∂z−∂H′z∂y=J′x+jωϵE′x
If we define x′=x, y′=y, z′=−z, (2) becomes
−∂H′y∂z′−∂H′z∂y′=J′x+jωϵE′x
that is, substituting the primed quantities with the equivalent unprimed ones,
−∂Hy∂z′+∂Hz∂y′=−Jx−jωϵEx
∂Hy∂z′−∂Hz∂y′=Jx+jωϵEx
The equation (2) can be written in the form (3): so, we have obtained the same equation as (1), but with respect to the primed variables!
Questions: can (3) still be considered a Maxwell's equation as well as (1)? Why?
My question arises because (3) is weird: it involves components of fields along the unprimed unit vectors (ux, uy and uz), and derivation with respect to the primed variables (x′, y′ and z′).
In particular, Hz has a different behaviour according to the system of coordinates, because uz=−uz′. So, how can this be taken into account while evaluating (3)? This is what I can't understand.
This demonstration is used to derive the fields in the Method of the Images in the Electromagnetic theory (the primed field is the image field).
No comments:
Post a Comment