It can't be Δ− since that is another particle also made up of quarks (not antiquarks). I can think of four possibilities:
- ¯Δ+
- ¯Δ+
- ¯Δ−
- ¯Δ−
I am sure someone has asked a similar question, but I failed at searching for it.
Answer
The Δ is a quartet of particles with isospin 3/2: Δ−,Δ0,Δ+,Δ++
I would expect the anti-Δ to be written ˉΔ, with the four isospin projections ˉΔ−−,ˉΔ−,ˉΔ0,ˉΔ+
In this case the antiparticle of the Δ+ would be the ˉΔ−.
If you'd like a canonical reference, look for a paper about pion production with antiproton beams. Note that there's a whole spectrum of Δ resonances, not just the lightest one at 1232 MeV.
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