Thursday 9 November 2017

classical mechanics - Moment of a force about a given axis (Torque) - Scalar or vectorial?


I am studying Statics and saw that:


The moment of a force about a given axis (or Torque) is defined by the equation:


$M_X = (\vec r \times \vec F) \cdot \vec x \ \ \ $ (or $\ \tau_x = (\vec r \times \vec F) \cdot \vec x \ $)


But in my Physics class I saw:


$\vec M = \vec r \times \vec F \ \ \ $ (or $\ \vec \tau = \vec r \times \vec F \ $)


In the first formula, the torque is a triple product vector, that is, a scalar quantity. But in the second, it is a vector. So, torque (or moment of a force) is a scalar or a vector?



Answer



It is obviously a vector, as you can see in the 2nd formula.


What you are doing in the first one is getting the $x$-component of that vector. Rememebr that the scalar product is the projection of one vector over the other one's direction. Actually you should write $\hat{x}$ or $\vec{i}$ or $\hat{i}$ to denote that it is a unit vector. That's because a unit vector satisfies



$\vec{v}\cdot\hat{u}=|v| \cdot |1|\cdot \cos(\alpha)=v \cos(\alpha)$


and so it is the projection of the vector itself.


In conclusion, the moment is a vector, and the first formula is only catching one of its components, as noted by the subindex.


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