Under a translation in spacetime i.e., x↦x′=x+a,
Question I'm a bit confused about step (1). Since the coordinates also change shouldn't we also change d4x→d4x′ in step (1)? I know that differentials don't change by adding a constant to a variable. In fact, that's what is used in arriving at step (3) from step (2). But the step (1) looks like ϕ(x) is mapped to ϕ′(x−a) and x is mapped to x. I'm suspicious whether it is d4x or really d4x′ (which is in turn equal to d4x) in step (1).
S2[ϕ] of AFT's answer Using (a) and (b), (when both the intergrand and dx are changed) we get, S2[ϕ]=∫x2ϕ(x)2dx↦∫(x+a)2ϕ(x−a)d(x+a)=∫(x+a)2ϕ(x−a)dx.
References
A Modern Introduction to Quanrum Field Theory Eq. 3.19, 3.20 and 3.21.
Field Quantization-W. Greiner Eq. 2.38, 2.39, and 2.45.
An introduction to Quantum Field theory- Peskin and Schroeder page 18.
Lectures on Classical Field Theory by Suresh Govindrajan
Lectures on Quantum Field Theory by Ashok Das page 212, Eq. 6.4
Relativistic Quantum Physics-Tommy Ohlsson Eq. 5.66, page 119.
A first book on quantum field theory by P. B. Pal Page 22, Eq. 2.38.
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