According to Gauss's Law, the electric field at a surface is the function of only the charge enclosed inside it. But that doesn't make sense. I mean, if I put the surface in an electric field, won't the resultant electric field at the surface change?
Subscribe to:
Post Comments (Atom)
-
I have an hydrogenic atom, knowing that its ground-state wavefunction has the standard form $$ \psi = A e^{-\beta r} $$ with $A = \frac{\bet...
-
At room temperature, play-dough is solid(ish). But if you make a thin strip it cannot just stand up on it's own, so is it still solid? O...
-
This image from NASA illustrates drag coefficients for several shapes: It is generally accepted that some variation of the teardrop/airfoil...
-
Sometimes I am born in silence, Other times, no. I am unseen, But I make my presence known. In time, I fade without a trace. I harm no one, ...
-
Sorry if this question is a bit broad but I can't find any info on this by just searching. The equation q = neAL where L is the length o...
-
I want to know what happens to the space a black hole crosses over as our galaxy travels through space.
-
Literature states neutral pion decay by QED cannot occur directly because the pion is uncharged. However, I cannot see why Photons are not a...
No comments:
Post a Comment