I am having trouble understanding the boundary conditions.
From the solutions, the first is that D1(0,t)=D2(0,t) because the rope can't break at the junction.
The second is that ∂D1∂xD1(0,t)=∂D2∂x(0,t). How can I interpret this physically? I'm not quite sure how to think about ∂D/∂x.
Answer
The second condition is saying that there is no discontinuity in the slope of the rope at the junction. In other words, there is no "kink" in the rope.
Imagine if this assumption were to fail in the following way: ∂D1∂x(0,t)=−1,∂D2∂x(0,t)=1
Addendum. Why can't there be a kink? In response to Nathaniel's response, here's why there can't be a kink. We argue by way of contradiction.
Suppose that there were a kink, and consider a small mass element centered on the junction. In the presence of a kink, the tensions on either side of the junction would point in different directions, and there would therefore be a net force on the small mass element. Now consider taking the size of that mass element to zero. There will be a net force on the mass element as we take the limit of its size to zero, but its mass will vanish, which yields a contradiction to Newton's second law.
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