Friday, 7 August 2020

special relativity - Potential energy in E2f=(mc2)2+(pc)2?


Let's consider


E2f=(mc2)2+(pc)2


where the mc2 is the rest energy due to the rest mass -- in Finnish "lepomassa".


(mc2)2+(pc)2mc2 = (γ1)mc2


is the kinetic energy due to the movement because of momentum p=γmv.


Now where is potential energy if Ef=γmc2 is the total energy?




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