Friday 7 August 2020

special relativity - Potential energy in $E_f^2=(mc^2)^2+(pc)^2$?


Let's consider


$$E_f^2=(mc^2)^2+(pc)^2$$


where the $mc^2$ is the rest energy due to the rest mass -- in Finnish "lepomassa".


$$ \sqrt{(mc^2)^2+(pc)^2} - mc^2~=~(\gamma-1)mc^2$$


is the kinetic energy due to the movement because of momentum $p=\gamma mv$.


Now where is potential energy if $E_f=\gamma mc^2$ is the total energy?




No comments:

Post a Comment

Understanding Stagnation point in pitot fluid

What is stagnation point in fluid mechanics. At the open end of the pitot tube the velocity of the fluid becomes zero.But that should result...