thermodynamics - Realistic calculation of heat loss for pipe

Good day everyone,

I am new on this site and I hope to find here help, since I am not going anywhere with the literature I have found.

I try to calculate realistically the heat loss of a hot, uninsulated pipe. Let's say, it is $170\,\,C$, 1 meter long, $8" (=0,203\,\,m)$ of diameter. I want to calculate the whole losses for the situation of no wind (only normal convection) and $20C$ of outside temperature.

The $170C$ is the temperature at the outside surface of the pipe, the surface is known, I also know the Stefan–Boltzmann constant ($\sigma$) and I take $\alpha=5$ for the convective coefficient of air at the surface of the pipe as well as $\epsilon=0.85$ for the steel pipe emissivity.

My problem is, that in literature, some parameter is always being rejected as negligible due to the fact, that most of the times the example is some kind of exercise of a heat transfer class. I want to calculate the real thing and then decide what is negligible and what is not. So my main question is: do I just add the radiation losses to the convective losses of the pipe ?

$$Q_{loss} = Q_{conv}+ Q_{rad}$$

$$= (\alpha*Α*\Delta T) + \epsilon*Α*\sigma*((T_{pipe})^4-(T_{air})^4) \tag{with T in K}$$

According the above, I get $Q_{conv} = 479\,\,W$ and $Q_{rad} = 958\,\,W$.

Is there any mistake in my way of thinking or is it truly that simple ?

Thanks in advance.

Marcus