Known that E=hf, p=hf/c=h/λ, then if p=mc, where m is the (relativistic) mass, then E=mc2 follows directly as an algebraic fact. Is this the case?
Answer
As you may know, photons do not have mass.
Relating relativistic momentum and relativistic energy, we get:
E2=p2c2+(mc2)2.
where E is energy, p is momentum, m is mass and c is the speed of light.
As mass is zero, E=pc.
Now, we know that E=hf. Then we get the momentum for photon.
Note that there is a term called effective inertial mass. Photon does have it.
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