Given the two-dimensional metric ds2=−r2dt2+dr2
I know that gμν=(−r2001) (this metric) and ημν=(−1001) (Minkowski). Obviously, the matrix transformation is (1/r2001)gμν=ημν, but how is that related to the coordinate transformation itself?
EDIT: would the following transformation be acceptable? r′=rcosht
And: ds′2=−dt′2+dr′2=−r2dt2+dr2=ds2
Where we have: ds′2=ημνdxμdxν as requested.
Is that correct? Also, is there a formal way of "deriving" the proper change of coordinates (since mine is more of an educated guess)?
Answer
If you were to Wick rotate t→iθ, the metric would be ds2=dr2+r2dθ2, which is just flat space in polar coordinates. The standard cartesian coordinates can be obtained by x=rcosθ, y=rsinθ. The same procedure works in the original Lorentzian signature metric, but with hyperbolic trig functions instead of sines and cosines.
By the way, this is two-dimensional Rindler space, which is just a patch of two-dimensional Minkowski space: http://en.wikipedia.org/wiki/Rindler_coordinates.
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