I have seen an expression for the angular momentum of a rotating sphere calculated from outside the sphere as L=Iω+mvr, where v is the velocity of the center of mass, m is the mass of the sphere, and r is the distance of center of mass of the sphere from the point of calculation. My concern is if v=0, then L=Iω, which is the angular momentum of the sphere when calculate through the center of mass. How can the angular momentum be the same when the point of calculation is changing?
Subscribe to:
Post Comments (Atom)
Understanding Stagnation point in pitot fluid
What is stagnation point in fluid mechanics. At the open end of the pitot tube the velocity of the fluid becomes zero.But that should result...
-
I have an hydrogenic atom, knowing that its ground-state wavefunction has the standard form ψ=Ae−βr with $A = \frac{\bet...
-
At room temperature, play-dough is solid(ish). But if you make a thin strip it cannot just stand up on it's own, so is it still solid? O...
-
Sometimes I am born in silence, Other times, no. I am unseen, But I make my presence known. In time, I fade without a trace. I harm no one, ...
-
I want to know what happens to the space a black hole crosses over as our galaxy travels through space.
-
I'm sitting in a room next to some totally unopened cans of carbonated soft drinks (if it matters — the two affected cans are Coke Zero...
-
Small vessels generally lean into a turn, whereas big vessels lean out. Why do ships lean to the outside, but boats lean to the inside of a ...
-
What exactly are the spikes, or peaks and valleys, caused by in pictures such as these Wikipedia states that "From the point of view of...
No comments:
Post a Comment