Three clocks are started at exactly the same time on Earth. The first and second clocks are taken into the vacuum of space.
The first clock accelerates until it reaches 100,000m/s, then stays at this speed for about two years. It decelerates, turns around, and re-accelerates back to 100,000m/s to return to earth.
The second clock accelerates away from earth for one year at a constant 9.5 m/s/s, which would make its top speed 299,592,000 m/s - very close to the speed of light (have I done my maths right here?). It then decelerates for one year at the same rate, and does the whole thing in reverse, accelerating and decelerating back towards earth at 9.5m/s/s.
Both return journeys of the first and second clock take exactly the same amount of time - 4 earth years.
The third clock remains on earth.
I think the first clock would be the most ahead, the second clock would be in the middle, and the third clock - the one that 'stayed still' on earth - would experience the most time dilation (be running the slowest), due the fact it is in a gravitational field with an effective 9.81 m/s/s rate of acceleration. Is this right?
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