Srednicki defines the exact propagator as ⟨0∣Tφ(x)φ(y)∣0⟩, where T is the time ordering symbol and x,y are four-vectors. What I am wondering is whether ∣0⟩ refers to the ground state of the free Hamiltonian or the perturbed one. I tried Googling this but found no clarification. If it is the perturbed vacuum then to what extent is the physical interpretation of φ(x)∣0⟩ as a point particle at x still valid?
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