Wave equations take the form:
∂2f∂t2=c2∇2f
But the Schroedinger equation takes the form:
iℏ∂f∂t=−ℏ22m∇2f+U(x)f
The partials with respect to time are not the same order. How can Schroedinger's equation be regarded as a wave equation? And why are interference patterns (e.g in the double-slit experiment) so similar for water waves and quantum wavefunctions?
Answer
Actually, a wave equation is any equation that admits wave-like solutions, which take the form f(→x±→vt). The equation ∂2f∂t2=c2∇2f, despite being called "the wave equation," is not the only equation that does this.
If you plug the wave solution into the Schroedinger equation for constant potential, using ξ=x−vt
−iℏ∂∂tf(ξ)=(−ℏ22m∇2+U)f(ξ)iℏvf′(ξ)=−ℏ22mf″
This clearly depends only on \xi, not x or t individually, which shows that you can find wave-like solutions. They wind up looking like e^{ik\xi}.
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