Thursday, 5 November 2015

homework and exercises - Can angular momentum not be conserved in a straight line motion?


Consider a particle moving an a straight line, with constant velocity v. The angular momentum (pivot point O) can be calculated as L=mrvθ

Where vθ is the velocity perpendicular to the vector r at each istant. enter image description here


Now if I calculate the angular momentum in A it get LA=mrAvx, while in B I get LB=mrBvy.


In general LALB but how can that be? How can angular momentum not be conserved? There are no forces, or torques!


I'm probably missing something big but I cannot see the mistake



Answer



If you draw similar triangles, then you'll find that rA/rB=vy/vx, and so the product rAvx is equal to rBvy. Try drawing a line from the tip of your lower v vector to the tip of your lower vy component to see this.


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