logical deduction - Can you solve this Bruce Wayne logic puzzle?

This variation of the classical Farmer Goat puzzle was in a puzzle contest at my college two years ago.
Here it goes.

Mr. Bruce Wayne is very fond of parties. Well, he’s more fond of girls, but, let’s just say that he’s fond of parties.
So, he plans a party at an island off the coast of Gotham Bay. All his guests have already reached. And we all know, Mr. Wayne likes to make an entrance. So, he decides to go in the chopper along with two supermodels. But unfortunately for Mr. Wayne, the chopper can hold only two people.

To add insult to the injury, the Mayor arrives with his two assistants to get a ride in the chopper. And there’s Mr. Fox, but with a secret case. Never mind, let’s just go to the party. But it seems someone doesn't want Mr. Wayne to enjoy tonight because there is no pilot to fly the chopper. And only Mr. Wayne, The Mayor and Mr. Fox know how to fly the chopper.

Oh no, wait! That’s not it. Mayor’s assistants won't stay with Mr. Wayne without their Mayor (I don’t know Bruce Wayne freaks them out); the supermodels won’t stay with the Mayor without Bruce (they think the Mayor is a pervert but Bruce isn't!) and Mr. Fox would never leave the case.

Let’s revise the situation.

The passenger list is:

1. Bruce Wayne


2. Bruce's 2 supermodels



3. Mayor


4. His 2 assistants


5. Mr. Fox


6. The secret case

And the constraints are:

• The capacity of the chopper is two persons.
  


• The secret case counts as a person (what, it's important!).


• Only Bruce, Mayor or Mr. Fox can fly the chopper.


• The Supermodels won’t stay with the Mayor without Bruce; Assistants won’t stay with Bruce without their Mayor and Mr. Fox won’t leave the case alone.

So much for making an entrance, Mr. Wayne! All things said and done, we still have a party to attend to. Now that you’ve understood the situation, help Mr. Wayne and his friends (and the case, too) reach the party.

I think I was able to solve this one, can you solve this puzzle?

Answer

Let me give it a try: Let's call the models B1 and B2 since they belong to B and the assistants M1 and M2 and the case F1.

B and M

B back

B and B1
B and M back

B and B2
B back

M and B
M back

F and F1
B back

B and M

M back

M and M1
B and M back

M and M2
M back

finally M and B