This is the first in what will hopefully be a series of Unsolved Mysteries posts.
Note that this puzzle has no known solution, nor any proof that a solution is impossible. We will see how smart the denizens of Puzzling.SE actually are...!
Most people are familiar with the concept of a Magic Square. (If not, follow the link to read up on it.)
There are algorithms available that make it trivial to construct a magic square of almost any size, but by adding a few constraints to the problem, it becomes much more challenging.
Consider the following 4×4 magic square, where every entry is itself a square number, and the rows, columns and diagonals all sum to 8515:
68229241237217231279232259228223261211277282492
Note that
682+292+412+372=172+312+792+322
but
68+29+41+37≠17+31+79+32
Only the squared values have the properties of a magic square.
Many such 4×4 squares have been constructed, but as of yet, no one has succeeded in constructing a 3×3 magic square with the same property, nor in proving that no such magic square exists.
Your challenge, therefore, is as follows:
A) Build a 3×3 magic square where each of the nine entries in the square is itself a square number.
or
B) Prove that no such square exists.
For the pedantic among us (you know who you are), here are a few additional constraints:
- Each entry in the square must be unique. (A square consisting entirely of 4s is not valid.)
- The definition of "square number" implies this, but I will spell it out here for those who like to quibble: The entries (before squaring) must be integers. Thus a magic square using values {√12,√22,√32,√42,√52,√62,√72,√82,√92} is not valid (although, of course, √12, √42, and √92 can be used in a square, being proper square numbers (=12,22,32).
- This also means that using complex numbers, limits, representations of infinity, or any other abstract mathematical concept is not valid. The intent of the question is obvious; please stick to that.
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