Is the energy carried by gravitational radiation a viable candidate for Λ / dark energy?
Answer
Nope. Gravitational radiation is a kind of radiation and it has a completely different equation of state than the cosmological constant.
The cosmological constant has pressure equal to the energy density with a minus sign, p=−ρ: the stress-energy tensor is proportional to the metric tensor so the spatial and temporal diagonal components only differ by the sign. Radiation has p=+ρ/3, much like for photons. Most of the energy density of the Universe has p/ρ=−1; that's what we know from observations because the expansion accelerates. A radiation-dominated Universe wouldn't accelerate (and didn't accelerate: our Universe was indeed radiation-dominated when it was much younger than today).
The ratio p/ρ must be between −1 and +1 because of the energy conditions (or because the speed of sound can't exceed the speed of light). The −1 bound is saturated by the cosmological constant, the canonical realization of "dark energy"; −2/3 and −1/3 comes from hypothetical cosmic domain walls and cosmic strings, respectively; 0 is the dust, i.e. static particles; +1/3 is radiation; and higher ratios may be obtained for "somewhat unrealistic" types of matter such as the dense black hole gas for which it is +1. This ratio determines the acceleration rate as a function of the Hubble constant.
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