I have a question regarding image formation by lenses. It is the following:
A lense with a focal length of −48.0cm forms an image 17.0cm to the right of the lense. Where is the object positioned?
My attempt at a solution:
Well, since the focal length is negative, we know that the lense is divergent (concave). The problem statement says that the image is to the right of the lense, so si=17cm(>0)
We can compute the position of the object by using the formula below:
1d0+1di=1f
Changing what we know for the values, we get:
1d0+117=−148
And doing the calculations, it comes down to:
s0=−12.55
However, the solutions say the solution is s0=26.3. One can get that if we take si to be negative, which is wrong, in my opinion. (?)
So, why am I wrong? Or am I correct?
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