Friday, 8 December 2017

kinematics - How to calculate the kinetic energy of supernova ejecta?


I believed I could use 0.5×MejV2ej, with Mej being the ejected mass and Vej being the velocity of the ejected mass. But I noticed in this and this that the the mean velocity is somehow calculated as following : Vmean=(3/5)0.5×Vej. And so the kinetic energy was calculated as : (3/5)(0.5)×MejV2mean=(3/10)×MejV2mean. So is there any explanation for how this factor of 0.3 or the mean velocity was calculated ?




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