I know that
$$\tag{1}\hat{p}~=~-i\hbar \frac{\partial}{\partial x}~.$$
How can I get
$$\tag{2}\hat{x}~=~i\hbar \frac{\partial}{\partial p}~?$$
I think this simple and I'm just over thinking it, but knowing the momentum operator (1), how can I get the position operator (2)?
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