The First Law can be stated as $\Delta U=Q-W$, where $W$ is the work done by the system. My question is what kind of work $W$ includes. $W$ certainly includes $PV$ work, i.e. expansion and compression of gas. Does it also include work on the system as a whole? For example, if the system is a billiard ball on a frictionless surface, and I push the billiard ball, doing positive work on it, increasing the kinetic energy of the ball. However, both $Q$ and $\Delta U$ are 0, so it seems this kind of work (me pushing the entire system) is not included in $W$. Am I correct? If so, what references spells this out? I was not able to find any references that specify the exclusion of this type of work.
Subscribe to:
Post Comments (Atom)
Understanding Stagnation point in pitot fluid
What is stagnation point in fluid mechanics. At the open end of the pitot tube the velocity of the fluid becomes zero.But that should result...
-
Why can't we use fissions products for electricity production ? As far has I know fissions products from current nuclear power plants cr...
-
As the title says. It is common sense that sharp things cut, but how do they work at the atomical level? Answer For organic matter, such a...
-
How can we know the order of a Feynman diagram just from the pictorial representation? Is it the number of vertices divided by 2? For exampl...
-
Yesterday, I understood what it means to say that the moon is constantly falling (from a lecture by Richard Feynman ). In the picture below ...
-
Consider the lagrangian of the real scalar field given by $$\mathcal L = \frac{1}{2} (\partial \phi)^2 - \frac{1}{2} m^2 \phi^2 - \frac{\lam...
-
Recently I was going through "Problems in General physics" by I E Irodov. In Electromagnetics chapter, there is a question how muc...
-
Literature states neutral pion decay by QED cannot occur directly because the pion is uncharged. However, I cannot see why Photons are not a...
No comments:
Post a Comment