Friday, 9 September 2016

radiation - Beta Decay Question


so this is bothering me a tad but why during calculations, do we subtract the masses of all electrons from both the original atom and the "new atom" and then subtract the mass for the emitted electron?


Let's say we have the beta decay:


$$\rm ^{14}_{6}C \to {}^{14}_{7}N + \beta^- + anti-neutrino$$


We neglect the mass for the anti-neutrino, so in the solution we have then the masses of both the C and N atoms and the electron emitted, and we subtract N and e^- from the C mass, but they also subtract all electron masses involved for both atoms,that is 6 electrons for C and 7 for N, why? And if so why doesn't the formula for beta decays show this too?




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