How and why would a particle take the shortest path?
L=KE−PE? What's the KE−PE mean in English?
I understand the 'mechanics' but not the idea itself.
Please explain simply, I do know Calculus but the simpler the better.
Please don't say because that's how nature is, because I get that a lot.
Answer
Borrowing from the new GR book by Anthony Zee, imagine that a boy on the beach, x1 meters from water, wants to get as quickly as possible to a drowning girl in the water, x2 meters from the beach, while the separation of the two people in the other direction parallel to the water-sand boundary is y. He won't pick the straight path because he's slower in the water, so the path through the water will be closer to orthogonal (to the water-sand boundary) than the path through the sand because it's "primarily" important to minimize the distance in the water.
You want to minimize the total time, which is t=t1+t2=s1/v1+s2/v2,v1>v2
It turns out that not only the trajectories of light and point masses but (almost) all possible laws of classical physics may be derived from such a minimization procedure, from δS=0, where S is the action. Almost always, S is the time integral ∫dtL where L is the Lagrangian.
In your example of simple mechanics, L=KE−PE where KE,PE are kinetic and potential energy, respectively. So L=mv2−V(x) is similar to the total energy H (also known as the Hamiltonian) except that there is an extra minus sign in front of the potential (but not kinetic) term.
This works because δS=0, after integrating by parts, gives you m¨x=F=−V′(x), the spatial derivative of the potential energy. When moved to the left hand side, both terms have a plus sign, which is OK even though the relative sign of PE,KE was minus because one of the minus signs disappears after we integrate over time by parts.
See also
and
Why the Principle of Least Action?
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