Sunday, 30 November 2014

electrostatics - What happens to half of the energy in a circuit with a capacitor?


For a simple circuit with a battery supplying a voltage $V$ to a capacitor, let us assume that the charge on the capacitor is $Q$. Now, the work done by the battery or the energy supplied is given by the relation:


$$W=QV$$


But the energy stored in the capacitor is given by:



$$U = \tfrac12 QV$$


The value of $Q$ as well as that of $V$ should be the same in both the equations.


Now my question is, where is the other half of the energy that the battery supplied?




No comments:

Post a Comment

Understanding Stagnation point in pitot fluid

What is stagnation point in fluid mechanics. At the open end of the pitot tube the velocity of the fluid becomes zero.But that should result...