For a simple circuit with a battery supplying a voltage $V$ to a capacitor, let us assume that the charge on the capacitor is $Q$. Now, the work done by the battery or the energy supplied is given by the relation:
$$W=QV$$
But the energy stored in the capacitor is given by:
$$U = \tfrac12 QV$$
The value of $Q$ as well as that of $V$ should be the same in both the equations.
Now my question is, where is the other half of the energy that the battery supplied?
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