I want to show that the Lorentz representation (1/2,1/2) corresponds to the normal vectorial representation Aμ. For this I need to show that the double spinors Aij=(Aμσμσ2)ij that transforms like Aij→(ΛR)ik(ΛL)jlAkl
implies that the Aμ transforms like Aμ→ΛμνAν.
But I really don't know how to even start this. Maybe I have issues understanding what is this representation. Here is what I did: A′μσμσ2=ΛRΛLAμσμσ2
Then multiply by σ2σν on the left and taking the trace Tr(σ2σνA′μσμσ2)=Tr(σ2σνΛRΛLAμσμσ2)2A′μδμν=Tr(σ2ΛRσ2ΛLAμδμν)2A′ν=Tr(Λ†LΛLAν)2A′ν=Tr(σ2Λ−1Lσ2ΛLAν)2A′ν=Aν
which can't be good.
EDIT:
I came up with a solution: A′ij=(ΛR)ik(ΛL)jlAkl(A′μσμσ2)ij=(ΛR)ik(Aμσμσ2)kl(ΛL)TljTr(σ2σνA′μσμσ2)=Tr(σ2σνΛRAμσμσ2ΛTL)Tr(σνA′μσμ)=Tr(σνΛRAμσμσ2ΛTLσ2)A′μTr(σνσμ)=Tr(σνΛRσμΛ∗R)Aμ2A′μδμν=Tr(σνΛRσμΛ∗R)AμA′ν=12Tr(σνΛRσμΛ∗R)AμA′ν=ΛμνAμ.
but I'm not sure why my indices are not good (compared to what I'm supposed to get Aμ′=ΛμνAν).
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