Wednesday, 24 December 2014

cipher - A not very easy puzzle with an easy answer. Something that a grim puzzler might like


1f411



pirate gibberish


00000010


1f607


.


1f441


1f44f


1f411


.


Cigarette ___


lion's-bane@



ワs


22 2


65 61 73 79


160 141 162 164


"2" & right(getMethod("mixintowater"), 5)


9 (4*2) 2 8 _ (4*3) (7*4) _ 6 (9*3) _ (6*2) 2 6 (3*2)?


Hint:



Unicode, guess, binary, Unicode - Unicode, Unicode, Unicode - guess, guess+symbols,Japanese,chemistry, ASCII, ASCII, code - ...





Answer



The last line is a telephone cipher.


A regular telephone keypad looks like this:


+-----+-----+-----+
| | ABC | DEF |
| | | |
| 1 | 2 | 3 |
+-----+-----+-----+
| GHI | JKL | MNO |
| | | |

| 4 | 5 | 6 |
+-----+-----+-----+
| PQRS| TUV | WXYZ|
| | | |
| 7 | 8 | 9 |
+-----+-----+-----+
| | | |
| * | 0 | # |
| | | |
+-----+-----+-----+


Given a character in the code, if there is just a single number (e.g. 2), you press that key once, to give the first letter on that number (i.e. A). If the character is a number "times" some other n (e.g. "7*4"), you press the key n times to get the nth letter for that number (i.e. S).


Doing so, you get the message:



WHAT IS MY NAME?



Which is, of course, Brent Hackers.


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