Sunday 7 June 2020

newtonian mechanics - What if exactly half the Earth's population jumped at one instant? + Secondary Question


I read somewhere that when you jump, the sole effect caused by your jump on the earth moves it about $10^{-18}m$ (I don't remember the figure exactly, but I think it was that).


However - obviously - with so many people running, jumping, etc. on the whole surface of the earth, the whole effect is canceled out, so it's safe to say there is no net displacement caused by us.


This got me to wonder, what if the whole population of one longitudinal hemisphere of the earth jumped at the exact same time - while the other half remained stationary - would we be able to notice any discernable displacement in the short time before we all land back to the ground?


Let's consider the earth to have a perfect distribution of people on both hemispheres, and let's consider the people of the Eastern Hemisphere to jump. Now the people jumping along the Prime Meridian and the International Date Line (these two lines together form the circle that divides the earth into the West and Eastern Hemispheres) would produce no effect, since they would simply cancel each other out. However, the closer you go to $0°N, 90°E$ (the centre of the East Hemisphere), the component of force which adds up will keep increasing. So there will be a net force in the direction of the Western Hemisphere. I was wondering if it would be noticeable.


enter image description here




Another question which just struck me: Out of all the satellites/rockets/space-shuttles we've sent out, have they caused any displacement on the earth? They are quite massive in comparison to us(not the earth, of course), and have large speeds. Many of them are continuously moving further and further away from the earth - so there's no question of them falling back to earth and thus shifting it to its original position again. Will the momentum be enough to displace the earth?




Answer



Some rough figures: earth's mass is about $6 10^{24}$ kg. The mass of the total world population is roughly 7 billion times 80 kg or about $6 10^{11}$ kg. So earth is 13 orders of magnitude (10 trillion times) more heavy than the world's human population.


Suppose that total mass of people gets together at one spot and everyone jumps up at the same time with a speed of about 1 m/s. The center of mass of earth plus all jumpers continues its trajectory, but momentum (mass times velocity) conservation dictates a recoil speed of $10^{-13}$ m/s for earth relative to the center of mass. That speed lasts for about a second and gets reversed due to gravitational attraction. When everyone lands on his/her feet earth is back at its normal trajectory.


The displacements (compared to the center of mass trajectory) follow the same mass ratio: if all the jumpers reach a respectable height of 1 m, earth gets displaced by $10^{-13}$ m (1/500th of the diameter of a hydrogen atom).


Distributing everyone over a hemisphere would reduce the effect by some factor. Hardly relevant, as there is no significant effect anyway.


No comments:

Post a Comment

Understanding Stagnation point in pitot fluid

What is stagnation point in fluid mechanics. At the open end of the pitot tube the velocity of the fluid becomes zero.But that should result...