Thursday, 15 January 2015

Conformal Field Theory in 1+1d Spontaneously Breaking Conformal Symmetry


Take any 1+1 dimensional conformal field theory on the plane. The Hamiltonian is invariant under the infinite-dimensional Virasoro algebra (with some central charge $c$), generated by $L_i$ ($i\in \mathbb Z$). However, the best one can do is find a ground state $|0\rangle$ which is symmetric w.r.t. $L_{i\geq -1}$ (this is also observed on the Wikipedia page). In other words, the ground state has much less symmetry than the Hamiltonian. This sounds like spontaneous symmetry breaking. Indeed, in footnote 3 of page 3 Maldacena and Stanford say:



In 1 +1 dimensional CFT the conformal symmetry is also spontaneously broken (recall that $L_{-2} |0\rangle \neq |0\rangle$), but it is not explicitly broken.



Can we really think of this as spontaneous symmetry breaking? If so: where is the infinite ground state degeneracy, where are the Goldstone modes, and what about Mermin-Wagner-Coleman even forbidding the breaking of a continuous symmetry? (And what about the slightly obscure Elitzur's 'theorem'/argument that forbids the spontaneous breaking of local symmetries?)


I can imagine some or all of these concerns being alleviated by somehow using the peculiar fact that the local generators $L_{i<-1}$ cannot be extended to global ones, i.e. the way the Virasoro algebra acts in this context cannot be interpreted as the Lie algebra of a Lie group [EDIT: this seems to be a common misconception, see the post by Bruce Bartlett]. Hence although the ground state breaks these local symmetries, there is no corresponding global symmetry being broken (which probably means Goldstone's theorem doesn't apply). Nevertheless I find it a bit hard to wrap my head around this: what is really being broken and what are its consequences? (and how are the aforementioned issues resolved?)


Note 1: This should not be confused with the conformal anomaly, which simply has to do with the fact that we have to replace the de Witt algebra by the Virasoro algebra.



Note 2: A related matter is the following: conformal symmetry (in this dimension) is a local symmetry. We are used to equating local symmetries to gauge symmetries, however at the same time I do not think we would want to call the conformal symmetry a gauge symmetry. Nevertheless, it is an interesting issue, since a gauge symmetry can of course never be broken (but this is perhaps a separate can of worms).




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